![]() ![]() Since the energy that comes through the hole you cut is spread out over a larger area, the intensity of the light decreases. The intensity of light is the power per area. (If you are using metric graph paper, try moving the graph paper at 2-cm increments.) The area illuminated will increase as the square of the distance. At 4 inches, sixteen squares will be illuminated, and so on. When the graph paper is moved 3 inches from the card, nine squares will be illuminated. When the graph paper is moved 2 inches from the card, four squares will be illuminated on the graph paper. A single square (measuring 1/2 inch) will be illuminated. At this distance, the graph paper touches the card. For example, adjust the distance from the bulb to the graph paper to 1 inch. As the distance from the bulb to the graph paper increases, the same amount of light spreads over a larger and larger area, and the light reaching each square becomes correspondingly less intense. Use graph paper with 1-cm squares printed on it.Īs you move the graph paper, light from the Mini Maglite spreads out equally in all directions.Position the card 2 centimeters in front of the light source.Follow the directions above, but instead of a 1/2 x 1/2-inch hole, cut out a 1 x 1-cm square hole in the center of the index card.Line up the Mini Maglight, square hole, and graph paper so when the light shines through the hole you see a square of light on the graph paper.Position the card one inch in front of the light source. ![]() Prop the light so it is at the same height as the square hole that you cut in the card.The bulb will come on and stay on when the reflector assembly is removed (see image below). Next, unscrew the front reflector assembly of the Mini Maglite to expose the bulb.Mount the graph paper on the side of the cardboard box or piece of foamcore to make a screen. ![]() Clip the binder clip to the bottom of the card to make a stand.Use your ruler and X-Acto knife to measure and cut out a 1/2 × 1/2-inch square in the center of the index card.If you are talking about Earth, there are some places where the acceleration due to gravity is different, but that is only due to abnormal events (Earth's buldge, mountains, etc. (It would also go higher which would mean more distance). For instance, if you would try this same experiment on the Moon, it would take longer for it to fall back since the acceleration due to gravity is slower. To answer your other question, the time does vary from place to place due to different gravity. This means that only at that small point of time, exactly at 6 seconds (to infinite precision of digits), it will have exactly 0 m/s. At 6.000000000000000000000000001 seconds, the object has velocity (which is really really really close to zero but not exactly zero). Only at exactly 6 seconds the ball has 0 m/s. This means that at 5.9999999999999999 seconds, the object still has some velocity. To visualize this, let's say for example, the object reaches zero velocity 6 seconds when it is thrown. The object will stay at 0 velocity for an infintensimally small time period (it doesn't last long). The gravitational field strength is directly proportional to mass creating the field and inversely proportional to the square of the distance. ![]() G g g g is the gravitational field strength SI units of m s 2 \dfrac g = m 2 F g = r 2 G m 1 g, equals, start fraction, F, start subscript, g, end subscript, divided by, m, start subscript, 2, end subscript, end fraction, equals, start fraction, G, m, start subscript, 1, end subscript, divided by, r, squared, end fraction The numerical value of the gravitational field at a point in space. Gravitational force ( F g F_g F g F, start subscript, g, end subscript )Īttractive force between two objects with mass.Ī model explaining the influence an object extends to produce a force on other objects. ![]()
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